0=x^2+(1*10^-5)x-(1*10^-6)

Solution for 0=x^2+(1*10^-5)x-(1*10^-6) equation:

0=x^2+(1*10^-5)x-(1*10^-6)

We move all terms to the left:

0-(x^2+(1*10^-5)x-(1*10^-6))=0

We add all the numbers together, and all the variables

-(x^2+(1*10^-5)x-(1*10^-6))=0


We calculate terms in parentheses: -(x^2+(1*10^-5)x-(1*10^-6)), so:

x^2+(1*10^-5)x-(1*10^-6)

We add all the numbers together, and all the variables

x^2+(1*10^-5)x-6-1.0E

We multiply parentheses

x^2+10x^2-5x-6-1.0E

We add all the numbers together, and all the variables

11x^2-5x-8.718281828459

Back to the equation:

-(11x^2-5x-8.718281828459)


We get rid of parentheses

-11x^2+5x+8.718281828459=0

a = -11; b = 5; c = +8.718281828459;
Δ = b2-4ac
Δ = 52-4·(-11)·8.718281828459
Δ = 408.6044004522
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{408.6044004522}}{2*-11}=\frac{-5-\sqrt{408.6044004522}}{-22}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{408.6044004522}}{2*-11}=\frac{-5+\sqrt{408.6044004522}}{-22}
$